25x+x^2=221

Solution for 25x+x^2=221 equation:

25x+x^2=221

We move all terms to the left:

25x+x^2-(221)=0

a = 1; b = 25; c = -221;
Δ = b2-4ac
Δ = 252-4·1·(-221)
Δ = 1509
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1509}}{2*1}=\frac{-25-\sqrt{1509}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1509}}{2*1}=\frac{-25+\sqrt{1509}}{2}
$